Equation
$y=ax^2+bx+c$
$f(x)=ax^2+bx+c$
$y=a(x−r_1)(x−r_2)$
$y=a(x−r_0)^2$
$f(x)=a(x−r_1)(x−r_2)$
$f(x)=a(x−r_0)^2$
$y=a(x−h)^2+k$
$f(x)=a(x−h)^2+k$
Opens up or down
If $a > 0$, parabola opens up (smiley).
If $a < 0$, parabola opens down (sad).
x-intercepts
$x={-b±√{b^2-4ac}}/{2a}$
- if ${b^2-4ac}>0$ - two intercepts
- if ${b^2-4ac}=0$ - one intercept
- if ${b^2-4ac}<0$ - no intercept
$x=r_1$ and $x=r_2$ (two intercepts)
or
$x=r_0$ (one intercept)
Solve for $x$ by setting $y=0$.
(Having a solution means one or two intercepts. No solution means no intercept.)
y-intercept
$c$
Solve for $y$ by setting $x=0$.
Axis (line) of symmetry
$x=-b/{2a}$
$x={r_1+r_2}/2$
$x=h$
Vertex
Calculate $x=-b/{2a}$. Substitute into equation to get y. Vertex is (x,y).
Calculate $x={r_1+r_2}/2$. Substitute into equation to get y. Vertex is (x,y).
$(h, k)$
Minimum / Maximum
Calculate the vertex.
If $a > 0$, $y$ is the minimum.
If $a < 0$, $y$ is the maximum.
If $a > 0$, $k$ is the minimum.
If $a < 0$, $k$ is the maximum.